159.Find Minimum in Rotated Sort
作者:
博瑜 | 来源:发表于
2017-07-06 08:12 被阅读0次public class Solution {
/**
* @param nums: a rotated sorted array
* @return: the minimum number in the array
*/
public int findMin(int[] nums) {
// write your code here
int length = nums.length;
int target = nums[length - 1];
int start = 0;
int end = length - 1;
while (start + 1 < end) {
int mid = start + (end - start) / 2;
if (nums[mid] < target) end = mid;
else start = mid;
}
if (nums[start] < nums[end]) return nums[start];
else return nums[end];
}
}
本文标题:159.Find Minimum in Rotated Sort
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