05替换空格

作者: gantrol | 来源:发表于2019-01-17 13:50 被阅读0次

    请实现一个函数,把字符串中的每个空格替换成"%20"。例如输入“We are happy.”,则输出“We%20are%20happy.”。

    # -*- coding:utf-8 -*-
    """
    其实,Python的字符串是不可变
    没有C++那种像字符串的问题,
    但这也导致了,必然多出了空间上的消耗。
    """
    def replaceSpace(strings):
        return strings.replace(' ', '%20')
    
    def my_replaceSpace(strings):
        result = ''
        for letter in strings:
            if letter == ' ':
                letter = '%20'
            result += letter
        return result
    
    # def replaceSpace2(strings):
    #     pieces = strings.split()
    #     result = ''
    #     for piece in pieces:
    #         result += piece + '%20'
    #     result -= '%20'  ## 不可行
    
    if __name__ == '__main__':
        assert replaceSpace('124322') == '124322'
        assert replaceSpace('124 322') == '124%20322'
        assert replaceSpace('123  4566 4356') == '123\%20\%204566\%204356'
        assert replaceSpace(' 124322') == '%20124322'
        assert replaceSpace('124322 ') == '124322%20'
        assert replaceSpace('') == ''
        assert replaceSpace('  ') == '124322%20'
        assert replaceSpace('   ') == '\%20\%20\%20'
    # 网站
    # https://www.nowcoder.com/practice/4060ac7e3e404ad1a894ef3e17650423?tpId=13&tqId=11155&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking
    

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