Problem
Given two arrays, write a function to compute their intersection.
Note:
- Each element in the result must be unique.
- The result can be in any order
Example
Input: nums1 = [1,2,2,1], nums2 = [2,2]
Output: [2]
Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
Output: [9,4]
Code
static int var = [](){
std::ios::sync_with_stdio(false);
cin.tie(NULL);
return 0;
}();
class Solution {
public:
vector<int> intersection(vector<int>& nums1, vector<int>& nums2) {
sort(nums1.begin(),nums1.end());
nums1.erase(unique(nums1.begin(),nums1.end()),nums1.end());
sort(nums2.begin(),nums2.end());
nums2.erase(unique(nums2.begin(),nums2.end()),nums2.end());
int i=0,j=0;
vector<int> res;
while(i<nums1.size()&&j<nums2.size()){
if(nums1[i]==nums2[j]){
res.push_back(nums1[i]);
i++;
j++;
}else if(nums1[i]<nums2[j]){
i++;
}else
j++;
}
return res;
}
};
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