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antd Table组件按照列字段组合进行行合并

antd Table组件按照列字段组合进行行合并

作者: 海豚先生的博客 | 来源:发表于2024-01-14 10:26 被阅读0次

场景:后端返回排好序的列表,前端按照将前几行按某一列字段进行行合并,后几行按照某几个列字段进行行合并,以实现1对2,2对4,4对8的table效果

// 页面使用,定义列字段参数
export function getContractColumns(): ProTableProps["columns"] {
  return [
    {
      title: "序号",
      dataIndex: "no",
      render(text: any, record: any, index: number) {
        return index + 1;
      },
      fixed: "left",
    },
    {
      title: "编号1",
      dataIndex: "contractNo1",
      // 根据编号1进行行合并
      rowMergeKey: ["contractNo1"],
    },
    {
      title: "编号2",
      dataIndex: "contractNo2",
      // 根据编号1和编号2,2个字段进行行合并
      rowMergeKey: ["contractNo1", "contractNo2"],
    },
]
// table自定义组件中
  const formatColumns = useCallback(() => {
    const dataSource = tableData;
    return (
      columns?.map((column:ProTableColumnConfig) => {
        return {
          ...column,
          // 关键代码----------start
          onCell: (rowData, rowIndex: number) => {
            if (column.rowMergeKey?.length && dataSource?.length) {
              const { rowMergeKey } = column;
              // 过滤条件
              const filters = {}
              // 关键字段拼接字符串
              let keyString = ''
              // 每列每行,行合并值
              const rowSpanMap = {}
              rowMergeKey.forEach((mergeKey: string) => {
                filters[mergeKey] = null;
              })
              forEach(dataSource, (row, i) => {
                const rowKeyString = rowMergeKey.map((mergeKey: string, i:number) => row[mergeKey]).join('-');
                if (rowKeyString !== keyString) {
                  // 重新赋值
                  forEach(filters, (v: any, k: string) => {
                    filters[k] = row[k]
                  })
                  // 计算当前行重复数
                  const rowSameCount = filterArrayByFilters(dataSource, filters).length;
                  rowSpanMap[i] = rowSameCount;
                  keyString = rowKeyString
                } else {
                  rowSpanMap[i] = 0;
                }
              })
              return { rowSpan: rowSpanMap[rowIndex] }
            }
            return {}
          }
         // 关键代码----------end
        };
      }) || []
    );
  }, []);

// 根据对象过滤数组
export function filterArrayByFilters(array: any, filters: any, startIndex: number) {
  let bool = true;
  let hasFirst = false;
  let preIndex = startIndex;
  
  return array.filter((obj: any, i: number) => {
    // 第一个重复没出现之前为true
    if (!hasFirst) {
      bool = true;
    }
    if (i < startIndex) {
      bool = false;
    }
    // 对每个过滤条件进行检查,确保对象符合所有条件
    const isRepeat = Object.keys(filters).every(key => {
      return (obj[key] === filters[key]) && bool;
    });
    // 紧挨着的才算重复次数
    if (isRepeat && !hasFirst) {
      hasFirst = true;
      bool = true;
      preIndex = i;
    } else if (hasFirst) {
      if (isRepeat && (i - preIndex === 1)) {
        bool = true;
        preIndex = i;
      } else {
        bool = false;
      }
    } else {
      bool = false;
    }

    return bool;
  });
}

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