async和await的执行顺序

首先贴一下教程：
http://dart.goodev.org/tutorials/language/futures

在async-and-await部分中，有一段代码，我修改了一下，如下

// Copyright (c) 2013, the Dart project authors.  Please see the AUTHORS file
// for details. All rights reserved. Use of this source code is governed by a
// BSD-style license that can be found in the LICENSE file.

import 'dart:html';
import 'dart:async';

Future printDailyNewsDigest() async {
  print('printDailyNewsDigest 1');//1
  String news = await gatherNewsReports();
  print('printDailyNewsDigest 2');//7
  print(news);//8
}

main() {
  printDailyNewsDigest();
  printWinningLotteryNumbers();//3
  printWeatherForecast();//4
  printBaseballScore();//5
}

printWinningLotteryNumbers() {
  print('Winning lotto numbers: [23, 63, 87, 26, 2]');
}

printWeatherForecast() {
  print('Tomorrow\'s forecast: 70F, sunny.');
}

printBaseballScore() {
  print('Baseball score: Red Sox 10, Yankees 0');
}

// Imagine that this function is more complex and slow. :)
Future gatherNewsReports() async {
  print('gatherNewsReports1');//2
  String path = 'https://www.dartlang.org/f/dailyNewsDigest.txt';
  var result = await HttpRequest.getString(path);
  print('gatherNewsReports2');//6
  return result;
}

其中后面注释的数字是我添加的，代表了输出顺序。
我看了下文档，总结了一下，在dart遇到await语句的时候，如果这个await调用的函数里还调用了其他async函数，比如上面的printDailyNewsDigest就又调用了gatherNewsReports，这时候printDailyNewsDigest会执行到gatherNewsReports函数里的await语句之前的代码，如果还有更多的await语句以此类推会一直执行到最后一个async的await语句之前然后返回Future，然后执行下面的非async部分的代码，在执行完以后会从最后一个await语句开始执行，然后就是上面的输出顺序。

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如果理解的不正确欢迎指正