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LeetCode 225题用队列实现栈(Implement St

LeetCode 225题用队列实现栈(Implement St

作者: 随机的未知 | 来源:发表于2020-02-03 08:18 被阅读0次

    链接

    https://leetcode-cn.com/problems/implement-stack-using-queues/

    思路

    首先演示push()操作;
    将元素依次进入队1,进入时用top元素保存当前进入的元素;
    如下图:

    push操作的演示

    然后演示pop()操作;
    先将除队1中的最后一个元素出队并进入队2,入队2时用top存储入队元素;
    再将队列1和队列2进行互换即可。
    如下图:

    pop操作的演示

    代码

    import java.util.LinkedList;
    import java.util.Queue;
    
    class MyStack {
    
        private Queue<Integer> queue_1 = new LinkedList<>();
        private Queue<Integer> queue_2 = new LinkedList<>();
        private int top;
        /** Initialize your data structure here. */
        public MyStack() {
    
        }
    
        /** Push element x onto stack. */
        public void push(int x) {
            queue_1.add(x);
            top = x;
        }
    
        /** Removes the element on top of the stack and returns that element. */
        public int pop() {
            if(empty()){
                throw new RuntimeException("MyStack空了!");
            }
            while(queue_1.size() > 1){
                top = queue_1.remove();
                queue_2.add(top);
            }
            int last_ele = queue_1.remove();
            Queue<Integer> queue_temp = queue_1;
            queue_1 = queue_2;
            queue_2 = queue_temp;
            return last_ele;
        }
    
        /** Get the top element. */
        public int top() {
            if(empty()){
                throw new RuntimeException("MyStack空了!");
            }
            return top;
        }
    
        /** Returns whether the stack is empty. */
        public boolean empty() {
            return queue_1.isEmpty() && queue_2.isEmpty() ;
        }
    }
    
    /**
     * Your MyStack object will be instantiated and called as such:
     * MyStack obj = new MyStack();
     * obj.push(x);
     * int param_2 = obj.pop();
     * int param_3 = obj.top();
     * boolean param_4 = obj.empty();
     */
    

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