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Web API中发送HTML表单数据:文件上传且带表单数据

Web API中发送HTML表单数据:文件上传且带表单数据

作者: A_Hello | 来源:发表于2018-07-26 18:50 被阅读0次
    参考资料

    https://docs.microsoft.com/en-us/aspnet/web-api/overview/advanced/sending-html-form-data-part-2

    代码实现
            [HttpPost]
            public async Task<HttpResponseMessage> UploadExcel()
            {
                /*
                 * 方法一:
                 */
                var result = await Request.Content.ReadAsMultipartAsync();
                var requestJson1 = await result.Contents[0].ReadAsStringAsync();
                var requestJson2 = await result.Contents[1].ReadAsStringAsync();
                var requestJson3 = await result.Contents[2].ReadAsStringAsync();
                var requestJson4 = await result.Contents[3].ReadAsStringAsync();
                //接收转Json
                var request = JsonConvert.DeserializeObject<List<Subjects>>(requestJson4);
    
                /*
                 * 方法二:
                 */
                var requestJson4 = await result.Contents
                if (!Request.Content.IsMimeMultipartContent())
                {
                    throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
                }
                string root = HttpContext.Current.Server.MapPath("~/App_Data");
                var provider = new MultipartFormDataStreamProvider(root);
                try
                {
                    await Request.Content.ReadAsMultipartAsync(provider);
                    //获取表单数据
                    foreach (var key in provider.FormData.AllKeys)
                    {
                        foreach (var val in provider.FormData.GetValues(key))
                        {
                            //Trace.WriteLine(string.Format("{0}: {1}", key, val));
                        }
                    }
    
                    //获取文件数据
                    if (HttpContext.Current.Request.Files.Count > 0)
                    {
                        var file=HttpContext.Current.Request.Files[0];                    
                    }
                    return Request.CreateResponse(HttpStatusCode.OK);
                }
                catch (System.Exception e)
                {
                    return Request.CreateErrorResponse(HttpStatusCode.InternalServerError, e);
                }
                return Request.CreateResponse(HttpStatusCode.OK);
            }
    

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