之前面试蘑菇街GG了,竟然是因为不懂UnionFind,来总结一下下啦。
def UnionFind(m, L):
temp = [i for i in range(m)]
for a, b in L:
if temp[a-1] == temp[b-1]:
continue
temp_a, temp_b = temp[a-1], temp[b-1] #这里是个坑,一定要这么写
for i in range(len(temp)):
if temp[i] == temp_b:
temp[i] = temp_a
return len(set(temp))
用BFS也是可以的啦~
import collections
def UnionFind2(m, L):
mydic = collections.defaultdict(list)
for a,b in L:
mydic[a].append(b)
mydic[b].append(a)
res = 0
visited = [0 for _ in range(m)]
for i in range(1,m+1):
if i in mydic and not visited[i-1]:
res += 1
BFS(mydic, visited, i)
print(i,res,visited)
return res + m - sum(visited)
def BFS(mydic, visited, index):
qu = [index]
while qu:
people = qu.pop(0)
visited[people-1] = 1
for f in mydic[people]:
if not visited[f-1]:
visited[people-1] = 1
qu.append(f)
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