在二叉搜索树中查找

描述

Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL.

For example, Given the tree:

    4
   / \
  2   7
 / \
1   3

And the value to search: 2
You should return this subtree:

  2     
 / \   
1   3

In the example above, if we want to search the value 5, since there is no node with value 5, we should return NULL.

代码

1. 递归

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    public TreeNode searchBST(TreeNode root, int val) {
        if (root == null || root.val == val) {
            return root;
        }
        
        if (root.val > val) {
            return searchBST(root.left, val);
        } else {
            return searchBST(root.right, val);
        }
    }
}

2. 迭代

class Solution {
    public TreeNode searchBST(TreeNode root, int val) {         
        while (root != null && root.val != val) {
            if (root.val > val) {
                root = root.left;
            } else {
                root = root.right;
            }
        }
        
        return root;
    }
}

注意如果不够仔细把if 条件句写反了则会返回空值