https://blog.csdn.net/helloxiaoliang/article/details/72723387
https://blog.csdn.net/DADADIE/article/details/50385146
// 两个浮点数求和
accAdd(num1, num2) {
var r1, r2, m;
try {
r1 = num1.toString().split('.')[1].length;
} catch (e) {
r1 = 0;
}
try {
r2 = num2.toString().split(".")[1].length;
} catch (e) {
r2 = 0;
}
m = Math.pow(10, Math.max(r1, r2));
// return (num1*m+num2*m)/m;
return Math.round(num1 * m + num2 * m) / m;
},
// 两个浮点数相减
accSub(num1, num2) {
var r1, r2, m;
try {
r1 = num1.toString().split('.')[1].length;
} catch (e) {
r1 = 0;
}
try {
r2 = num2.toString().split(".")[1].length;
} catch (e) {
r2 = 0;
}
m = Math.pow(10, Math.max(r1, r2));
n = (r1 >= r2) ? r1 : r2;
return (Math.round(num1 * m - num2 * m) / m).toFixed(n);
},
// 两数相除
accDiv(num1, num2) {
var t1, t2, r1, r2;
try {
t1 = num1.toString().split('.')[1].length;
} catch (e) {
t1 = 0;
}
try {
t2 = num2.toString().split(".")[1].length;
} catch (e) {
t2 = 0;
}
r1 = Number(num1.toString().replace(".", ""));
r2 = Number(num2.toString().replace(".", ""));
return (r1 / r2) * Math.pow(10, t2 - t1);
},
//两数相乘
accMul(num1, num2) {
var m = 0,
s1 = num1.toString(),
s2 = num2.toString();
try {
m += s1.split(".")[1].length
} catch (e) {};
try {
m += s2.split(".")[1].length
} catch (e) {};
return Number(s1.replace(".", "")) * Number(s2.replace(".", "")) / Math.pow(10, m);
}
网友评论