F(0) = 0
F(1) = 1
F(n) = F(n-1)+F(n-2) (n>=2)
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递推下去变成
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的来由
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问题已经描述完,接下来就是如何求解矩阵幂。
reference:https://blog.csdn.net/wjlwangluo/article/details/105252473
F(0) = 0
F(1) = 1
F(n) = F(n-1)+F(n-2) (n>=2)
的来由
问题已经描述完,接下来就是如何求解矩阵幂。
reference:https://blog.csdn.net/wjlwangluo/article/details/105252473
本文标题:斐波那契数列矩阵求法
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