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13. 异步爬虫

13. 异步爬虫

作者: 薛东弗斯 | 来源:发表于2024-03-01 21:50 被阅读0次

1. 串行执行

import requests

headers = {
    'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.121 Safari/537.36'
}
urls = [
    'https://downsc.chinaz.net/Files/DownLoad/jianli/202306/zjianli1756.rar',
    'https://downsc.chinaz.net/Files/DownLoad/jianli/202306/zjianli1756.rar',
    'https://downsc.chinaz.net/Files/DownLoad/jianli/202306/zjianli1756.rar'
]

def get_content(url):
    print('正在爬取:',url)
    #get方法是一个阻塞的方法
    response = requests.get(url=url,headers=headers)
    if response.status_code == 200 :
        return response.content

def parse_content(content):
    print('响应数据的长度为:',len(content))


for url in urls:
    content = get_content(url)
    parse_content(content)

4个线程串行执行,共花8秒

import time
# 单线程串行方式执行

def get_page(str):
    print("downloading...", str)
    time.sleep(2)
    print("download succeed:", str)

name_list = ['aa', 'bb', 'cc', 'dd']
start_time = time.time()
for i in range(len(name_list)):
    get_page(name_list[i])
end_time = time.time()
print("%d seconds passed!" % (end_time - start_time))

线程池,执行时间为2秒

import time
# 导入线程池模块对应的类
from multiprocessing.dummy import Pool

start_time = time.time()
def get_page(str):
    print("downloading...", str)
    time.sleep(2)
    print("download succeed:", str)

name_list = ['aa', 'bb', 'cc', 'dd']
pool = Pool(4)
# 将列表中每个列表元素传递给get_page进行处理
pool.map(get_page,name_list)
end_time = time.time()
print("%d seconds passed!" % (end_time - start_time))

li 视频

import requests
from lxml import etree
import re
from multiprocessing.dummy import Pool
#需求:爬取梨视频的视频数据
headers = {
    'User-Agent':'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3578.98 Safari/537.36'
}
#原则:线程池处理的是阻塞且较为耗时的操作,不期望能处理所有的操作

#对下述url发起请求解析出视频详情页的url和视频的名称
url = 'https://www.pearvideo.com/category_5'
page_text = requests.get(url=url,headers=headers).text

tree = etree.HTML(page_text)
li_list = tree.xpath('//ul[@id="listvideoListUl"]/li')
urls = [] #存储所有视频的链接and名字
for li in li_list:
    detail_url = 'https://www.pearvideo.com/'+li.xpath('./div/a/@href')[0]
    name = li.xpath('./div/a/div[2]/text()')[0]+'.mp4'
    #对详情页的url发起请求
    detail_page_text = requests.get(url=detail_url,headers=headers).text
    #从详情页中解析出视频的地址(url)
    ex = 'srcUrl="(.*?)",vdoUrl'
    video_url = re.findall(ex,detail_page_text)[0]
    dic = {
        'name':name,
        'url':video_url
    }
    urls.append(dic)
#对视频链接发起请求获取视频的二进制数据,然后将视频数据进行返回
def get_video_data(dic):
    url = dic['url']
    print(dic['name'],'正在下载......')
    data = requests.get(url=url,headers=headers).content
    #持久化存储操作
    with open(dic['name'],'wb') as fp:
        fp.write(data)
        print(dic['name'],'下载成功!')
#使用线程池对视频数据进行请求(较为耗时的阻塞操作)
pool = Pool(4)
pool.map(get_video_data,urls)

pool.close()
pool.join()

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