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字符串去重

字符串去重

作者: 7_c5dc | 来源:发表于2019-05-19 21:33 被阅读0次
    void RemoveDuplicate(char *str)
    {
        int i, j, k;
        unsigned long len = strlen(str);
        for(i = k = 0; i < len; i++) {
            if(str[i]) {
                str[k++] = str[i];
                for(j = i + 1; j < len; j++)
                    if(str[j] == str[i])
                        str[j] = '\0';
            }
        }
        str[k] = '\0';
    }
    
    
    void RemoveDuplicate1(char *s) {
        char check[256] = { 0 };
        int j = 0;
        unsigned long len = strlen(s);
        for(int i = 0; i < len; i++)  {
            if(check[s[i]] == 0) {
                s[j++] = s[i];
                check[s[i]] = 1;
            }
        }
        s[j] = '\0';
    }
    
    void RemoveDuplicate3(char *s) {
        int remainder;
        int check[8] = {0}; //4个字节 * 8 * 8bit = 256bit
        int j = 0;
        unsigned long len = strlen(s);
        for(int i = 0; i < len; i++)  {
            remainder = s[i] % 32; //remainder 范围0-31
            //s[i] >> 5是确定在数组中哪个位置
    
            printf("%d -- %d--%d", s[i] >> 5, check[s[i] >> 5], remainder);
            printf("\n");
            if((check[s[i] >> 5] & (1 << remainder)) == 0) {
                s[j++] = s[i];
                check[s[i] >> 5] |= (1 << remainder);
            }
        }
        s[j] = '\0';
    }
    
    void RemoveDuplicate2(char *s)
    {
        int i, j, val, check;
        j = check = 0;
        for(i = 0; s[i]; i++)
        {
            val = s[i] - 'a';
            if((check & (1 << val)) == 0)
            {
                s[j++] = s[i];
                check |= 1 << val;
            }
        }
        s[j] = '\0';
    }
    
    

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