美文网首页
JS逆向之融金所sign分析

JS逆向之融金所sign分析

作者: 布丁和尚 | 来源:发表于2021-12-11 14:49 被阅读0次

    篇幅有限

    完整内容及源码关注公众号:ReverseCode,发送

    https://m.rjs.com/member/user.html#1

    抓包

    登录url:

    POST https://m.rjs.com/japi/account/login.json

    请求头:

    :authority: m.rjs.com
    :method: POST
    :path: /japi/account/login.json
    :scheme: https
    accept: application/json, text/plain, */*
    accept-encoding: gzip, deflate, br
    accept-language: zh-CN,zh;q=0.9
    content-length: 172
    content-type: application/json
    cookie: riskTipTimes1=1; Hm_lvt_7ff1e43d61e6b35b46f6bb33c3aba9bb=1618099071; Hm_lpvt_7ff1e43d61e6b35b46f6bb33c3aba9bb=1618099071
    datatype: json
    origin: https://m.rjs.com
    referer: https://m.rjs.com/member/user.html
    sec-ch-ua: "Google Chrome";v="89", "Chromium";v="89", ";Not\"A\\Brand";v="99"
    sec-ch-ua-mobile: ?1
    sec-fetch-dest: empty
    sec-fetch-mode: cors
    sec-fetch-site: same-origin
    User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/50.0.2661.87 Safari/537.36
    

    参数:

    {"platform":"wap","session_token":"","session_id":"","data":{"userName":"15806204085","password":"123"},"sign":"b6a20a0b1c82b87d65b78b2943bb3fbc","timestamp":1618099099626}
    

    分析

    搜索japi/account/login.json 无果

    搜索account/login.json

    loginAction: function() {
        if (this.checkLoginKey() && this.checkLoginPwd()) {
            var e = this;
            c.Common.fajax({
                url: "account/login.json",
                easyOriginData: {
                    userName: e.loginKey,
                    password: e.loginPwd
                },
                success: function(t) {
                    1 == t.status ? (c.Common.cookie.set("session_token_dp", t.data.sessionToken, "/", "/", 168),
                    c.Common.cookie.set("platform", "wap", "/", "/", 168),
                    c.Common.localStore.set("session_token_dp", t.data.sessionToken),
                    c.Common.localStore.set("uid_dp", t.data.uid),
                    c.Common.cookie.set("secretKey", t.data.secretKey, "/", "/", 168),
                    c.Common.alert("simpleSuccess", "登录成功", 1, e.goHref, "/member-undp/index.html")) : e.alert(t.message)
                }
            })
        }
    },
    

    打上断点调试,此时并没有出现sign,说明sign应该是在fajax中生成,进入fajax中,逐步调试,t["sign"] = i(f + "&" + i(o.genSignData(t.data)) + "&" + d),这一步出现了sign进行填值,f为/account/login.json

    image-20210411184621104

    d是""空字符串

    image-20210411184650658

    接下来分析i(o.genSignData(t.data))中的o.genSignData(t.data),其中t.data为账户密码的对象

    image-20210411184839858

    genSignData

    i(o.genSignData(t.data))分析,先进入o.genSignData函数,拆分出来js如下

    var genSignData = function(e) {
        var t = ""
          , n = [];
        for (var r in e)
            n.push(r);
        n = n.sort();
        for (var i = 0; i < n.length; i++) {
            var o = n[i]
              , s = e[o]
              , l = !1;
            if ("object" == ("undefined" == typeof s ? "undefined" : (0,
            a.default)(s))) {
                var c = "{";
                for (var u in s)
                    c += u + "=" + s[u] + ", ",
                    l = !0;
                l && (s = c.substring(0, c.length - 2) + "}")
            }
            "sign" != o && null !== s && void 0 !== s && "" !== s && ("object" != ("undefined" == typeof s ? "undefined" : (0,
            a.default)(s)) || l) && (t += (0 == i ? "" : "&") + o + "=" + s)
        }
        return null != t && "" != t && "&" == t.substr(0, 1) && (t = t.substr(1, t.length)),
        t
    }
    

    单独运行时报错Uncaught ReferenceError: a is not defined,打印a.default

    image-20210411185111684

    进入a.default,该三元运算所得结果即为控制台打印结果,必然前面的是完全匹配的

     t.default = "function" == typeof s.default && "symbol" === l(a.default) ? function(e) {
        return "undefined" == typeof e ? "undefined" : l(e)
    }
    

    该l函数在上面也有定义如下

    image-20210411185437746

    那么我们定义函数k即a.default如下,替换genSignData完成函数解密password=123&userName=15806204095

    var k = function(e){
        return"undefined"==typeof e?"undefined": typeof e
    }
    

    i

    i(o.genSignData(t.data))分析,接下来就是i函数的分析,进入i函数

    image-20210411124238222

    第一次调用i函数时,先调用o函数进行加密,再调用wordsToBytes转成字节,返回bytesToHex生成16进制字符串,整体逻辑理清后进入o函数。

    o

    image-20210411185814560

    该函数中引用了n(694),n(247).utf8,n(974),n(247).bin,通过debug可知以上都生成了加密函数

    image-20210411185946412

    这些加密函数搜索分别发现出现在了694:function,247:function等等,可以断定,这些函数其实就是作为变量在o函数中调用

    image-20210411190204917 image-20210411190338395

    扣出694,247,974的代码如下

    var liu94 = function (e, t) {
            var t = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"
                , n = {
                    rotl: function (e, t) {
                        return e << t | e >>> 32 - t
                    },
                    rotr: function (e, t) {
                        return e << 32 - t | e >>> t
                    },
                    endian: function (e) {
                        if (e.constructor == Number)
                            return 16711935 & n.rotl(e, 8) | 4278255360 & n.rotl(e, 24);
                        for (var t = 0; t < e.length; t++)
                            e[t] = n.endian(e[t]);
                        return e
                    },
                    randomBytes: function (e) {
                        for (var t = []; e > 0; e--)
                            t.push(Math.floor(256 * Math.random()));
                        return t
                    },
                    bytesToWords: function (e) {
                        for (var t = [], n = 0, r = 0; n < e.length; n++,
                            r += 8)
                            t[r >>> 5] |= e[n] << 24 - r % 32;
                        return t
                    },
                    wordsToBytes: function (e) {
                        for (var t = [], n = 0; n < 32 * e.length; n += 8)
                            t.push(e[n >>> 5] >>> 24 - n % 32 & 255);
                        return t
                    },
                    bytesToHex: function (e) {
                        for (var t = [], n = 0; n < e.length; n++)
                            t.push((e[n] >>> 4).toString(16)),
                                t.push((15 & e[n]).toString(16));
                        return t.join("")
                    },
                    hexToBytes: function (e) {
                        for (var t = [], n = 0; n < e.length; n += 2)
                            t.push(parseInt(e.substr(n, 2), 16));
                        return t
                    },
                    bytesToBase64: function (e) {
                        for (var n = [], r = 0; r < e.length; r += 3)
                            for (var i = e[r] << 16 | e[r + 1] << 8 | e[r + 2], a = 0; a < 4; a++)
                                8 * r + 6 * a <= 8 * e.length ? n.push(t.charAt(i >>> 6 * (3 - a) & 63)) : n.push("=");
                        return n.join("")
                    },
                    base64ToBytes: function (e) {
                        e = e.replace(/[^A-Z0-9+\/]/gi, "");
                        for (var n = [], r = 0, i = 0; r < e.length; i = ++r % 4)
                            0 != i && n.push((t.indexOf(e.charAt(r - 1)) & Math.pow(2, -2 * i + 8) - 1) << 2 * i | t.indexOf(e.charAt(r)) >>> 6 - 2 * i);
                        return n
                    }
                };
            return n;
    }
    
    var er47 = {
        utf8: {
            stringToBytes: function (e) {
                return er47.bin.stringToBytes(unescape(encodeURIComponent(e)))
            },
            bytesToString: function (e) {
                return decodeURIComponent(escape(er47.bin.bytesToString(e)))
            }
        },
        bin: {
            stringToBytes: function (e) {
                for (var t = [], n = 0; n < e.length; n++)
                    t.push(255 & e.charCodeAt(n));
                return t
            },
            bytesToString: function (e) {
                for (var t = [], n = 0; n < e.length; n++)
                    t.push(String.fromCharCode(e[n]));
                return t.join("")
            }
        }
    };
    
    var jiu74 = function (e, t) {
        function n(e) {
            return !!e.constructor && "function" == typeof e.constructor.isBuffer && e.constructor.isBuffer(e)
        }
        function r(e) {
            return "function" == typeof e.readFloatLE && "function" == typeof e.slice && n(e.slice(0, 0))
        }
        return function (e) {
            return null != e && (n(e) || r(e) || !!e._isBuffer)
        }
    }
    

    在o函数中改写t,r,i,a

        var t = liu94()
            , r = er47.utf8
            , i = jiu74()
            , a = er47.bin
    

    最终只要将o函数中exports的函数return出来即可

    res = function (e, n) {
        console.log(e)
        if (void 0 === e || null === e)
            throw new Error("Illegal argument " + e);
        var r = t.wordsToBytes(o(e, n));
        console.log(r)
        return n && n.asBytes ? r : n && n.asString ? a.bytesToString(r) : t.bytesToHex(r)
    }
    //res("password=123&userName=158062204095", undefined);
    //console.log('-------->',res(origin, undefined))
    return res;
    

    由于o(e,n)中的即为o.genSignData生成的账密参数password=123&userName=15806204095,n为undefined,那么我们就可以直接调用该方法返回真正的sign。

    console.log(encrypt()("/account/login.json"+"&"+encrypt()(genSignData(UP))+"&"+""));

    image-20210411191326027

    查看抓包后的结果如下

    image-20210411191409718

    爬虫实现

    import json
    
    import requests
    import execjs
    
    username = "15806204095"
    psssword = "123"
    with open(r'rjs_sign.js', encoding='utf-8', mode='r') as f:
        JsData = f.read()
    sign = execjs.compile(JsData).call('request',username,psssword)
    data = json.dumps({"platform":"wap","session_token":"","session_id":"","data":{"userName":username,"password":psssword},"sign":sign,"timestamp":1618153079455})
    r =requests.post("https://m.rjs.com/japi/account/login.json",data)
    print(r.text)
    

    完整源码请关注微信公众号:ReverseCode,回复:JS逆向

    本文由博客群发一文多发等运营工具平台 OpenWrite 发布

    相关文章

      网友评论

          本文标题:JS逆向之融金所sign分析

          本文链接:https://www.haomeiwen.com/subject/gamkfrtx.html