公式测试
Fisher信息
[latex]I(\theta) = -E[(\frac{\partial \ln L}{\partial\theta})][/latex]
![]( "http://latex.codecogs.com/gif.latex?I(\theta)&space;=&space;-E[(\frac{\partial&space;\ln&space;L}{\partial\theta})]" )
I(\theta) = -E[(\frac{\partial \ln L}{\partial\theta})]
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