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8.23 cc 数组和字符串[pt2]

8.23 cc 数组和字符串[pt2]

作者: 陈十十 | 来源:发表于2016-08-23 13:46 被阅读15次

    to do

    • cc150 array&string (6-11)/11
    • leetcode review day 1

    1.6] Rotate N*N matrix by 90 degrees

    Rotate Image

    • note how to use start and end to keep track easily
        void rotate(vector<vector<int>>& matrix) {
            int n = matrix.size();
            for (int layer=0; layer<matrix.size()/2; ++layer) {
                int start = layer, end = start+(n-1);
                for (int i=start; i<end; ++i) {
                    int tmp = matrix[start][i];
                    matrix[start][i] = matrix[end-(i-start)][start];
                    matrix[end-(i-start)][start] = matrix[end][end-(i-start)];
                    matrix[end][end-(i-start)] = matrix[i][end];
                    matrix[i][end] = tmp;
                }
                n-=2;
            }
        }
    

    1.7] Given M*N matrix, clear row and col where 0 occurs

    Set Matrix Zeroes
    check~ note the last for loop, to avoid repeatly setting zeros

        void setZeroes(vector<vector<int>>& matrix) {
            if (matrix.empty() || matrix[0].empty()) return;
            int m = matrix.size(), n = matrix[0].size();
            vector<bool> shouldSetRow(m, false);
            vector<bool> shouldSetCol(n, false);
            for (int i=0; i<m; ++i) {
                for (int j=0; j<n; ++j) {
                    if (!matrix[i][j]) {
                        shouldSetRow[i] = true;
                        shouldSetCol[j] = true;
                    }
                }
            }
            for (int i=0; i<m; ++i) {
                for (int j=0; j<n; ++j) {
                    if (shouldSetRow[i] || shouldSetCol[j])
                        matrix[i][j] = 0;
                }
            }
        }
    

    1.8] 假设提供了isSubstring,可以检查strA是否为strB的子串。给定两个字符串s1和s2,判断是否s2由s1旋转而来,只可用isSubstring一次。

    恩不剧透了,想不出看P116

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