还是豆瓣，现在学爬虫先爬豆瓣都成一种行规了，别的不多说，今天用的一个pyquery，很好用，是模仿jquery的，比xpath还简单，直接看代码。

import os
import requests
from pyquery import PyQuery as pq

class Model(object):
"""
基类, 用来显示类的信息
"""
def repr(self):
name = self.class.name
properties = ('{}=({})'.format(k, v) for k, v in self.dict.items())
s = '\n<{} \n {}>'.format(name, '\n '.join(properties))
return s

class Movie(Model):
"""
存储电影信息
"""
def init(self):
self.name = ''
self.score = 0
self.quote = ''
self.cover_url = ''
self.ranking = 0

def cached_url(url):
"""
缓存, 避免重复下载网页浪费时间
"""
folder = 'cached'
filename = url.split('=', 1)[-1] + '.html'
'cached/0.html'
path = os.path.join(folder, filename)
if os.path.exists(path):
with open(path, 'rb') as f:
s = f.read()
return s
else:
# 建立 cached 文件夹
if not os.path.exists(folder):
os.makedirs(folder)

    headers = {
        'user-agent': '''Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/57.0.2987.98 Safari/537.36

Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,/;q=0.8''',
}
# 发送网络请求, 把结果写入到文件夹中
r = requests.get(url, headers)
with open(path, 'wb') as f:
f.write(r.content)
return r.content

def movie_from_div(div):
"""
从一个 div 里面获取到一个电影信息
"""
e = pq(div)

# 小作用域变量用单字符
m = Movie()
m.name = e('.title').text()
m.score = e('.rating_num').text()
m.quote = e('.inq').text()
m.cover_url = e('img').attr('src')
m.ranking = e('.pic').find('em').text()

return m

def movies_from_url(url):
"""
从 url 中下载网页并解析出页面内所有的电影
"""
'''
只会下载一次
'''
page = cached_url(url)
'''
1. 解析 dom
2. 找到父亲节点
3. 每个子节点拿一个movie
'''
e = pq(page)
# print(page.decode())
# 2.父节点
items = e('.item')
# 调用 movie_from_div
# list comprehension
movies = [movie_from_div(i) for i in items]
return movies

def download_image(url):
folder = "img"
name = url.split("/")[-1]
path = os.path.join(folder, name)

if not os.path.exists(folder):
    os.makedirs(folder)

if os.path.exists(path):
    return

headers = {
    'user-agent': '''Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/57.0.2987.98 Safari/537.36
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8''',
}
# 发送网络请求, 把结果写入到文件夹中
r = requests.get(url, headers)
with open(path, 'wb') as f:
    f.write(r.content)

def main():
for i in range(0, 250, 25):
url = 'https://movie.douban.com/top250?start={}'.format(i)
movies = movies_from_url(url)
print('top250 movies', movies)
[download_image(m.cover_url) for m in movies]

if name == 'main':
main()