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java基础数据结构-map源码分析

java基础数据结构-map源码分析

作者: yuanjian | 来源:发表于2017-09-18 15:42 被阅读0次

    1.HashMap

    HashMap实际上是一个节点数组table,只不过数组的索引是通过hash算法计算出来的。每一个节点都包含一个key,一个value,key的hash值,以及下一个节点next。jdk1.7中解决碰撞问题是通过链表实现的,所以会存next节点。图1是map中节点的定义。

    图1
    • 1.1 put(K key, V value)
      • a) 先通过hash(key)求出key的hash值,源码见图2和图3
    图2 图3
    • b) 判断当前map是否初始化,已初始化则跳过此步骤,没有初始化则调用resize()方法初始化map,此步骤中需要注意的几个点,全局变量和常量:threshold(变量,表示下次扩容时的map长度),loadFactor (常量,值为0.75,threshold=map.size()*loadFactor)。当map.size() == threshold时就会调用resize()方法进行扩容,扩容一倍。源码见图4,resize()源码较长直接贴出来。
    图4
    final Node<K,V>[] resize() {
            Node<K,V>[] oldTab = table;
            int oldCap = (oldTab == null) ? 0 : oldTab.length;
            int oldThr = threshold;
            int newCap, newThr = 0;
            if (oldCap > 0) {
                if (oldCap >= MAXIMUM_CAPACITY) {
                    threshold = Integer.MAX_VALUE;
                    return oldTab;
                }
                else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY &&
                         oldCap >= DEFAULT_INITIAL_CAPACITY)
                    newThr = oldThr << 1; // double threshold
            }
            else if (oldThr > 0) // initial capacity was placed in threshold
                newCap = oldThr;
            else {               // zero initial threshold signifies using defaults
                newCap = DEFAULT_INITIAL_CAPACITY;
                newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY);
            }
            if (newThr == 0) {
                float ft = (float)newCap * loadFactor;
                newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ?
                          (int)ft : Integer.MAX_VALUE);
            }
            threshold = newThr;
            @SuppressWarnings({"rawtypes","unchecked"})
                Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
            table = newTab;
            if (oldTab != null) {
                for (int j = 0; j < oldCap; ++j) {
                    Node<K,V> e;
                    if ((e = oldTab[j]) != null) {
                        oldTab[j] = null;
                        if (e.next == null)
                            newTab[e.hash & (newCap - 1)] = e;
                        else if (e instanceof TreeNode)
                            ((TreeNode<K,V>)e).split(this, newTab, j, oldCap);
                        else { // preserve order
                            Node<K,V> loHead = null, loTail = null;
                            Node<K,V> hiHead = null, hiTail = null;
                            Node<K,V> next;
                            do {
                                next = e.next;
                                if ((e.hash & oldCap) == 0) {
                                    if (loTail == null)
                                        loHead = e;
                                    else
                                        loTail.next = e;
                                    loTail = e;
                                }
                                else {
                                    if (hiTail == null)
                                        hiHead = e;
                                    else
                                        hiTail.next = e;
                                    hiTail = e;
                                }
                            } while ((e = next) != null);
                            if (loTail != null) {
                                loTail.next = null;
                                newTab[j] = loHead;
                            }
                            if (hiTail != null) {
                                hiTail.next = null;
                                newTab[j + oldCap] = hiHead;
                            }
                        }
                    }
                }
            }
            return newTab;
        }
    
    • c) 通过(table.length - 1) & hash计算value的索引,table.length通过位运算计算,始终为2的n次方,索引通过&计算得出,始终在数组范围内。当此索引的节点为null时,直接实例化一个节点存进去,如果此索引的节点值不为null,则会对比此节点key的值,key值相同则覆盖,否则遍历此索引上的节点链表,在链表的尾部存入新的节点。源码见图5。
    final V putVal(int hash, K key, V value, boolean onlyIfAbsent,
                       boolean evict) {
            Node<K,V>[] tab; Node<K,V> p; int n, i;
            if ((tab = table) == null || (n = tab.length) == 0)
                n = (tab = resize()).length;
            if ((p = tab[i = (n - 1) & hash]) == null)  //计算当前节点的索引,并判断节点是否为null,为null则直接创建新的节点
                tab[i] = newNode(hash, key, value, null);
            else { // 此key的索引位置已有节点
                Node<K,V> e; K k;
                //判断key是否重复
                if (p.hash == hash &&
                    ((k = p.key) == key || (key != null && key.equals(k))))
                    e = p;
                else if (p instanceof TreeNode)
                    e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
                else { //key值不重复,存链表
                    for (int binCount = 0; ; ++binCount) {
                        if ((e = p.next) == null) {
                            p.next = newNode(hash, key, value, null);
                            if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
                                treeifyBin(tab, hash);
                            break;
                        }
                        if (e.hash == hash &&
                            ((k = e.key) == key || (key != null && key.equals(k))))
                            break;
                        p = e;
                    }
                }
                if (e != null) { // existing mapping for key
                    V oldValue = e.value;
                    if (!onlyIfAbsent || oldValue == null)
                        e.value = value;
                    afterNodeAccess(e);
                    return oldValue;
                }
            }
            ++modCount;
            // 当size > threshold时,重置map的size
            if (++size > threshold)
                resize();
            afterNodeInsertion(evict);
            return null;
        }
    
    • 1.2 get(Object key)
      • a) 先根据hash(key)算法求key的hash值
      • b) 然后通过(table.length - 1) & hash求出value所处的位置
      • c) 通过比对该位置的key值是否相等来获取value值,如果不等且节点不为空,jdk1.7中走链表进行匹配查找value。

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