函数:
function ajaxFn(url, data, params) {
// url:接口地址; data:请求参数; params:请求方式(get/post)
return new Promise(function(resolve, reject) {
$.ajax({
url: http+url,
type: params,
// dataType: params && params.dataType || 'JSON',
dataType: 'json',
data: data,
success: function(res) {
resolve(res)
},
error: function(res) {
alert(res.msg)
}
});
});
}
使用方法:
var data={
userId: localStorage.getItem('userId')//用户ID
}
ajaxFn(urlObj.core, data, 'GET').then(function(res){
if(res.code==200){
console.log(res)
}else{
alert(res.msg)
}
})
网友评论