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ATM简易模拟(C语言)

ATM简易模拟(C语言)

作者: 零散的蒲公英 | 来源:发表于2019-07-29 21:30 被阅读0次

    简易的实现了ATM的工作流程

    代码逻辑并不多,主要是对循环的使用,而且做的比较简易,任然有些bug未去解决

    代码如下:

    int main()
    {
        int choice = 0;
        int password = 123;
        int scanpwd = 0;
        int money = 1000000;
        int chance = 3;
        int Imoney = 0;
        printf("*******************\n");
        printf("欢迎光临\n");
        printf("*******************\n请输入密码:");
        while (1){  
        scanf("%d",&scanpwd);
        if (scanpwd == password) {
            break;
        }else{  
            chance--;
            if (chance > 0){
            printf("*******************\n");
            printf("输入密码错误,请重新输入,您还有%d次机会\n",chance);
            printf("*******************\n");
            printf("请重新输入密码:");
            }else{
              printf("*******************\n");
              printf("输入错误次数达到上限,账号也被冻结,请到柜台解锁\n");
              exit(EXIT_FAILURE);
            }
          }
        }
        while (1){
          printf("*******************\n");
          printf("1.取款\n");
          printf("2.存款\n");
          printf("3.更改密码\n");
          printf("4.退出\n");
          printf("*******************\n");
          printf("请选择功能:");
          while (1){
              scanf("%d",&choice);
              if (choice > 0&&choice < 5){
                  break;
              }
              else {
                  printf("请输入正确的序号:");
              }
          }
          switch (choice){
          case 1:
              printf("请输入取款金额:");
              scanf("%d",&Imoney);
              money = money - Imoney;
              while (1){
                  if (money > 0) {
                      printf("取款成功,余额:%d\n", money);
                      break;
                  }else{
                      printf("余额不足\n");
                      break;
                  }
              }
              break;
          case 2:
              printf("请输入存款金额:");
              scanf("%d",&scanpwd);
              money = money + scanpwd;
              printf("存款成功,余额为:%d\n",money);
              break;
          case 3:
              printf("请输入原密码:");
              scanf("%d",&scanpwd);
              if (scanpwd == password){
                  printf("请输入新密码:");
                  scanf("%d", &scanpwd);
                  password = scanpwd;
                  printf("请确认新密码:");
                  scanf("%d", &scanpwd);
                  if (scanpwd == password){
                      printf("密码更改成功!!!\n");
                      password = scanpwd;
                  }else{
                      printf("两次密码不一致,请重新设置密码\n");
                  }
              }else{
                  printf("密码错误!!!\n");
              }
              break;
          case 4:
              exit(EXIT_SUCCESS);
          default:
              break;
          }
        }
        return 0;
    }
    

    以上的代码能够简易的实现ATM机的工作流程,嗯,,,重点是简易
    代码测试内容如下:


    代码测试

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