Array:Given an array of integers
作者:
敲一手烂代码 | 来源:发表于
2016-06-12 17:07 被阅读16次public int singleNumber1(int[] nums) {
HashMap<Integer, Integer> hashMap = new HashMap<Integer, Integer>();
for (int i = 0; i < nums.length; i++) {
if (hashMap.containsKey(nums[i])) {
if (hashMap.get(nums[i])==2) {
hashMap.remove(nums[i]);
} else {
hashMap.put(nums[i], hashMap.get(nums[i])+1);
}
} else {
hashMap.put(nums[i], 1);
}
}
for (int i : hashMap.keySet()) {
return i;
}
return -1;
}
本文标题:Array:Given an array of integers
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