Given an array of integers, find if the array contains any duplicates.
Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.
Example 1:
Input: [1,2,3,1]
Output: true
Example 2:
Input: [1,2,3,4]
Output: false
class Solution:
def containsDuplicate(self, nums: List[int]) -> bool:
if len(nums)==len(set(nums)):
return(False)
else:
return(True)
Runtime: 124 ms, faster than 84.43% of Python3 online submissions for Contains Duplicate.
Memory Usage: 18 MB, less than 88.68% of Python3 online submissions for Contains Duplicate.
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