问题:
项目中需要设置电话号码输入时如xxx xxxx xxxx的格式
自定义控件代码:
import UIKit
class PhoneField: UITextField {
//保存上一次的文本内容
var _previousText:String!
//保持上一次的文本范围
var _previousRange:UITextRange!
override init(frame: CGRect) {
super.init(frame: frame)
setupUI()
}
required init?(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
setupUI()
}
func setupUI() {
//默认边框样式为圆角矩形
self.borderStyle = UITextField.BorderStyle.none
//使用数字键盘
self.keyboardType = UIKeyboardType.numberPad
}
//当本视图的父类视图改变的时候
override func willMove(toSuperview newSuperview: UIView?) {
//监听值改变通知事件
if newSuperview != nil {
NotificationCenter.default.addObserver(self,
selector: #selector(phoneNumberFormat(_:)),
name: UITextField.textDidChangeNotification,
object: nil)
}else{
NotificationCenter.default.removeObserver(self,
name: UITextField.textDidChangeNotification,
object: nil)
}
}
//输入框内容改变时对其内容做格式化处理
@objc func phoneNumberFormat(_ notification: Notification) {
let textField = notification.object as! UITextField
if(!textField.isEqual(self)){ return }
guard let selectedTextRange = textField.selectedTextRange else { return }
//当前光标的位置(后面会对其做修改)
var cursorPostion = textField.offset(from: textField.beginningOfDocument,
to: selectedTextRange.start)
//过滤掉非数字字符,只保留数字
let digitsText = getDigitsText(string: textField.text!,
cursorPosition: &cursorPostion)
//避免超过11位的输入
if digitsText.count > 11 {
textField.text = _previousText
textField.selectedTextRange = _previousRange
return
}
//得到带有分隔符的字符串
let hyphenText = getHyphenText(string: digitsText, cursorPosition: &cursorPostion)
//将最终带有分隔符的字符串显示到textField上
textField.text = hyphenText
//让光标停留在正确位置
guard let targetPostion = textField.position(from: textField.beginningOfDocument,
offset: cursorPostion) else{ return }
textField.selectedTextRange = textField.textRange(from: targetPostion,
to: targetPostion)
//现在的值和选中范围,供下一次输入使用
_previousText = self.text!
_previousRange = selectedTextRange
}
//除去非数字字符,同时确定光标正确位置
func getDigitsText(string:String, cursorPosition:inout Int) -> String{
//保存开始时光标的位置
let originalCursorPosition = cursorPosition
//处理后的结果字符串
var result = ""
var i = 0
//遍历每一个字符
for uni in string.unicodeScalars {
//如果是数字则添加到返回结果中
if CharacterSet.decimalDigits.contains(uni) {
result.append(string[i])
}
//非数字则跳过,如果这个非法字符在光标位置之前,则光标需要向前移动
else{
if i < originalCursorPosition {
cursorPosition = cursorPosition - 1
}
}
i = i + 1
}
return result
}
//将分隔符插入现在的string中,同时确定光标正确位置
func getHyphenText(string:String, cursorPosition:inout Int) -> String {
//保存开始时光标的位置
let originalCursorPosition = cursorPosition
//处理后的结果字符串
var result = ""
//遍历每一个字符
for i in 0 ..< string.count {
//如果当前到了第4个、第8个数字,则先添加个分隔符
if i == 3 || i == 7 {
result.append(" ")
//如果添加分隔符位置在光标前面,光标则需向后移动一位
if i < originalCursorPosition {
cursorPosition = cursorPosition + 1
}
}
result.append(string[i])
}
return result
}
}
//通过对String扩展,字符串增加下表索引功能
extension String
{
subscript(index:Int) -> String
{
get{
return String(self[self.index(self.startIndex, offsetBy: index)])
}
set{
let tmp = self
self = ""
for (idx, item) in tmp.enumerated() {
if idx == index {
self += "\(newValue)"
}else{
self += "\(item)"
}
}
}
}
}
上面的代码只能根据输入改变格式,如果直接设置号码的话就会无用
这时候可以用NumberFormatter
下面为解决方法
private lazy var phoneFormatter:NumberFormatter = {
let _formatter = NumberFormatter.init()
_formatter.groupingSeparator = " "
_formatter.groupingSize = 4
_formatter.usesGroupingSeparator = true
return _formatter
}()
调用:
phoneTextField.text = phoneFormatter.string(from: NSNumber.init(value:"12345678901"))
记得点赞哦
网友评论