题目链接
https://leetcode.com/problems/remove-nth-node-from-end-of-list/
解题思路
先链表反转,再删除,最后再反转。(看题解的思路更简单)
代码
class Solution {
public:
ListNode* removeNthFromEnd(ListNode* head, int n) {
if (head == NULL) {
return NULL;
}
head = revert(head);
if (n == 1) {
head = head -> next;
} else {
ListNode *cur = head, *next = head->next;
for (int i = 2; i < n; ++i) {
cur = next;
next = cur->next;
}
cur->next = next->next;
}
return revert(head);
}
ListNode* revert(ListNode *head) {
if (head == NULL || head->next == NULL) {
return head;
}
ListNode *end = head, *tmp;
head = head->next;
end->next = NULL;
while (head != NULL) {
tmp = head->next;
head->next = end;
end = head;
head = tmp;
}
return end;
}
};
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