题目
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Note: A leaf is a node with no children.
Example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its depth = 3.
分析
这个题目是求二叉树的最大深度,很容易想像为 一个节点的最大深度等于子节点的最大深度+1 。用递归即可实现
代码
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def maxDepth(self, root: TreeNode) -> int:
if not root:
return 0 # 空节点最大深度为0
rdepth = self.maxDepth(root.right) #左节点最大深度
ldepth = self.maxDepth(root.left) #右节点最大深度
return max(rdepth, ldepth)+1 #每个节点最大深度= 子节点最大深度+1
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