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2018-08-08

2018-08-08

作者: 埃尔温薛定谔不养猫 | 来源:发表于2018-08-08 12:52 被阅读0次
    SELECT a.`count` fans_num, c.introduce, c.area, 
     CASE 
     WHEN b.user_id IS NULL THEN '0' 
     ELSE '1' 
     END as is_follow 
     FROM ( 
     SELECT follow_user_id, count(*) as `count` FROM tt_user_follow WHERE follow_user_id =   v 
     ) as a 
     LEFT JOIN ( 
     SELECT user_id FROM tt_user_follow WHERE user_id =   v   && follow_user_id =   str_user_id 
     ) AS b 
     ON a.follow_user_id = b.user_id 
     LEFT JOIN ( 
     SELECT user_id, introduce, area FROM tt_user_auth WHERE user_id =   v 
     ) AS c 
     ON a.follow_user_id = c.user_id;
    

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