public static int reverse(int x) {
if (x>=0) {
int p = 0;
while (x>0) {
p = p * 10 + x % 10;
System.out.println(p);
x /= 10;
}
return p;
} else {
x = -x;
int p = 0;
while (x>0) {
p = p * 10 + x % 10;
x /= 10;
}
return -p;
}
}
https://leetcode-cn.com/problems/reverse-integer/
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https://leetcode.com/problems/reverse-integer/description...
https://leetcode.com/problems/reverse-integer/description...
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题目：https://leetcode.cn/problems/reverse-integer/[https://...
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本文标题：Other:reverse-integer
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