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SpringMVC异常处理

SpringMVC异常处理

作者: 落雪无尘V | 来源:发表于2020-12-05 20:51 被阅读0次

    Spring MVC处理异常有3种方式:

    (1)使用Spring MVC提供的简单异常处理器SimpleMappingExceptionResolver;

    (2)实现Spring的异常处理接口HandlerExceptionResolver 自定义自己的异常处理器;

    (3)使用@ExceptionHandler注解实现异常处理;

    1. 集成异常处理

    使用SimpleMappingExceptionResolver实现异常处理

    1、在Spring的配置文件springMVC.xml中增加以下内容:

    <bean class="org.springframework.web.servlet.handler.SimpleMappingExceptionResolver"> 
      <!-- 定义默认的异常处理页面,当该异常类型的注册时使用 -->
      <property name="defaultErrorView" value="error"></property> 
      <!-- 定义异常处理页面用来获取异常信息的变量名,默认名为exception -->
      <property name="exceptionAttribute" value="ex"></property> 
      <!-- 定义需要特殊处理的异常,用类名或完全路径名作为key,异常也页名作为值 -->
      <property name="exceptionMappings"> 
        <props> 
          <prop key="cn.basttg.core.exception.BusinessException">error-business</prop> 
          <prop key="cn.basttg.core.exception.ParameterException">error-parameter</prop> 
      
          <!-- 这里还可以继续扩展对不同异常类型的处理 -->
        </props> 
      </property> 
    </bean> 
    

    2.实现HandlerExceptionResolver 接口自定义异常处理器

    增加HandlerExceptionResolver 接口的实现类MyExceptionHandler,代码如下:

    public class MyExceptionHandler implements HandlerExceptionResolver { 
      
      public ModelAndView resolveException(HttpServletRequest request, HttpServletResponse response, Object handler, 
          Exception ex) { 
        Map<String, Object> model = new HashMap<String, Object>(); 
        model.put("ex", ex); 
          
        // 根据不同错误转向不同页面 
        if(ex instanceof BusinessException) { 
          return new ModelAndView("error-business", model); 
        }else if(ex instanceof ParameterException) { 
          return new ModelAndView("error-parameter", model); 
        } else { 
          return new ModelAndView("error", model); 
        } 
      } 
    } 
    

    2、在Spring的配置文件springMVC.xml中增加以下内容:

    <bean id="exceptionHandler" class="cn.basttg.core.exception.MyExceptionHandler"/> 
    

    3.使用@ExceptionHandler注解实现异常处理

    增加CrowdExceptionResolver 类,并在类中使用@ExceptionHandler注解声明异常处理,代码如下:

    public class CrowdExceptionResolver {
        /**
         * 空指针异常
         */
        @ExceptionHandler(value = NullPointerException.class)
        public ModelAndView resolverNullPointerException(NullPointerException exception, HttpServletRequest request, HttpServletResponse response) throws IOException {
            return commonResolver("system-error", exception,request,response);
        }
        /**
         * 数学异常
         */
        @ExceptionHandler(value = ArithmeticException.class)
        public ModelAndView resolverNullPointerException(ArithmeticException e, HttpServletRequest request, HttpServletResponse response) throws IOException {
            System.out.println(e.getMessage());
            return commonResolver("system-error", e,request,response);
        }
    
    
    
        /**
         * 通用异常处理
         * @param viewName 跳转视图名字
         * @param e  异常类型
         * @param request 请求
         * @param response 响应
         * @return
         * @throws IOException
         */
       protected ModelAndView  commonResolver(String viewName ,Exception e, HttpServletRequest request, HttpServletResponse response) throws IOException {
           boolean requestJson = CrowdUtil.isRequestAjax(request);
           if (requestJson){//Ajax请求
               ResultEntity<Object> resultEntity = ResultEntity.failed(e.getMessage());
               String json = new Gson().toJson(resultEntity);
               response.getWriter().write(json);
               return null;
           }
           ModelAndView modelAndView = new ModelAndView();
           modelAndView.addObject("exception",e);
           modelAndView.setViewName("system-error");
           return modelAndView;
       }
    }
    

    2、修改代码,使所有需要异常处理的Controller都继承该类,如下所示,修改后的TestController类继承于BaseController:

    public class TestController extends CrowdExceptionResolver 
    

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