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Day8作业

Day8作业

作者: 圣咸鱼 | 来源:发表于2019-01-03 16:43 被阅读0次

    使用一个变量all_students保存一个班的学生信息(4个),每个学生需要保存:姓名、年龄、成绩、电话

    all_students = [
        {'name':'stu1', 'age': 19, 'score':81, 'tel':'192222'},
        {'name':'stu2', 'age': 29, 'score':90, 'tel':'211222'},
        {'name':'stu3', 'age': 12, 'score':67, 'tel':'521114'},
        {'name':'stu4', 'age': 30, 'score':45, 'tel':'900012'},
    ] 
    

    1.添加学生:输入学生信息,将输入的学生的信息保存到all_students中

    例如输入:
    姓名: 小明
    年龄: 20
    成绩: 100
    电话: 111922  
    那么就在all_students中添加{'name':'小明', 'age': 20, 'score': 100, 'tel':'111922'}
    
    all_students = [
    {'name': 'stu1', 'age': 19, 'score': 81, 'tel': '192222'},
    {'name': 'stu2', 'age': 29, 'score': 90, 'tel': '211222'},
    {'name': 'stu3', 'age': 12, 'score': 67, 'tel': '521114'},
    {'name': 'stu4', 'age': 30, 'score': 45, 'tel': '900012'},
    ]
    n1 = input('请输入学生姓名:')
    n2 = input('请输入学生年龄:')
    n3 = input('请输入学生成绩:')
    n4 = input('请输入学生电话:')
    dict1 = {'name': n1,  'age': n2, 'score': n3, 'tel': n4}
    all_students.append(dict1)
    print(all_students)
    

    2.按姓名查看学生信息:

    例如输入:
    姓名: stu1 就打印:'name':'stu1', 'age': 19, 'score':81, 'tel':'192222'
    
    all_students = [
    {'name': 'stu1', 'age': 19, 'score': 81, 'tel': '192222'},
    {'name': 'stu2', 'age': 29, 'score': 90, 'tel': '211222'},
    {'name': 'stu3', 'age': 12, 'score': 67, 'tel': '521114'},
    {'name': 'stu4', 'age': 30, 'score': 45, 'tel': '900012'},
    ]
    n1 = input('请输入学生姓名:')
    for dict1 in all_students:
        for key in dict1:
            if dict1[key] == n1:
                print(dict1)
    

    3.求所有学生的平均成绩和平均年龄

    all_students = [
    {'name': 'stu1', 'age': 19, 'score': 81, 'tel': '192222'},
    {'name': 'stu2', 'age': 29, 'score': 90, 'tel': '211222'},
    {'name': 'stu3', 'age': 12, 'score': 67, 'tel': '521114'},
    {'name': 'stu4', 'age': 30, 'score': 45, 'tel': '900012'},
    ]
    sum1 = 0
    sum2 = 0
    for dict1 in all_students:
        for key in dict1:
            if key == 'score':
                sum1 += dict1[key]
            elif key == 'age':
                sum2 += dict1[key]
    print('平均成绩为:%d' % (sum1 // len(all_students)))
    print('平均年龄为:%d' % (sum2 // len(all_students)))
    
    

    4.删除班级中年龄小于18岁的学生

    all_students = [
    {'name': 'stu1', 'age': 19, 'score': 81, 'tel': '192222'},
    {'name': 'stu2', 'age': 29, 'score': 90, 'tel': '211222'},
    {'name': 'stu3', 'age': 12, 'score': 67, 'tel': '521114'},
    {'name': 'stu4', 'age': 30, 'score': 45, 'tel': '900012'},
    ]
    for dict1 in all_students[:]:
        for key in dict1:
            if key == 'age' and dict1[key] < 18:
                all_students.remove(dict1)
    print(all_students)
    

    5.统计班级中不及格的学生的人数

    all_students = [
    {'name': 'stu1', 'age': 19, 'score': 81, 'tel': '192222'},
    {'name': 'stu2', 'age': 29, 'score': 90, 'tel': '211222'},
    {'name': 'stu3', 'age': 12, 'score': 67, 'tel': '521114'},
    {'name': 'stu4', 'age': 30, 'score': 45, 'tel': '900012'},
    ]
    num =0
    for dict1 in all_students:
        for key in dict1:
            if key == 'score' and dict1[key] < 60:
                num += 1
    print('不及格的人数为:%d人' % num)
    

    6.打印手机号最后一位是2的学生的姓名

    all_students = [
    {'name': 'stu1', 'age': 19, 'score': 81, 'tel': '192222'},
    {'name': 'stu2', 'age': 29, 'score': 90, 'tel': '211222'},
    {'name': 'stu3', 'age': 12, 'score': 67, 'tel': '521114'},
    {'name': 'stu4', 'age': 30, 'score': 45, 'tel': '900012'},
    ]
    names = []
    for dict in all_students:
        sum = int(dict['tel'])
        if sum % 10 == 2:
             name = dict['name']
             names.append(name)
    print(names)
    

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