题目链接
https://leetcode.com/problems/find-first-and-last-position-of-element-in-sorted-array/
解题思路
先找左边界,再找右边界
代码
class Solution {
public:
vector<int> searchRange(vector<int>& nums, int target) {
vector<int> ans;
int left = findLeft(nums, target, 0, nums.size() - 1);
ans.push_back(left);
if (left == -1) {
ans.push_back(-1);
} else {
ans.push_back(findRight(nums, target, left, nums.size() - 1));
}
return ans;
}
int findLeft(vector<int>& nums, int target, int l, int r) {
if (l > r) {
return -1;
}
if (target == nums[l]) {
return l;
}
int m = (l + r) / 2;
if (nums[m] > target) {
return findLeft(nums, target, l, m - 1);
} else if (nums[m] == target) {
return findLeft(nums, target, l, m);
} else {
return findLeft(nums, target, m + 1, r);
}
}
int findRight(vector<int>& nums, int target, int l, int r) {
if (l > r) {
return -1;
}
if (target == nums[r]) {
return r;
}
int lr = l + r;
int m = lr / 2;
if (lr & 1) {
m++;
}
if (nums[m] > target) {
return findRight(nums, target, l, m - 1);
} else if (nums[m] == target) {
return findRight(nums, target, m, r);
} else {
return findRight(nums, target, m + 1, r);
}
}
};
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