Well, we can also solve in dp format.
Python3
@functools.lru_cache(None)
def leastOpsExpressTarget(self, x, y):
k = int(math.log(y, x)) + 1
def dfs(y, k):
if k == 0 or y == 0:
return y + y - 1
need, left = divmod(y, x**k)
return min(dfs(left, k - 1) + need * k, dfs(x**k - left, k - 1) + (need + 1) * k)
return dfs(y, k)
Well, we can also solve in dp format.Python3
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本文标题：Leetcode 964.Least Operators to
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