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2. Add Two Numbers

2. Add Two Numbers

作者: HalcyonMoon | 来源:发表于2016-06-28 14:10 被阅读0次

    You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
    Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
    Output: 7 -> 0 -> 8
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    /**
     * Definition for singly-linked list.
     * public class ListNode {
     *     int val;
     *     ListNode next;
     *     ListNode(int x) {
     *         val = x;
     *         next = null;
     *     }
     * }
     */
    public class Solution {
        public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
            int carry = 0;
            ListNode p, head = new ListNode(0);
            p = head;
            while(l1!=null || l2!=null || carry!=0){
                int number = carry;
                if(l1 != null){
                    number += l1.val;
                    l1 = l1.next;
                }
                if(l2 != null){
                    number += l2.val;
                    l2 = l2.next;
                }
                if(number >9 ){
                    carry = 1;
                    number = number%10;
                }else{
                    carry = 0;
                }
                p.next = new ListNode(number);
                p = p.next;
            }
            return head.next;
        }
    }
    

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