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350. Intersection of Two Arrays

350. Intersection of Two Arrays

作者: a_void | 来源:发表于2016-09-16 16:17 被阅读0次

iven two arrays, write a function to compute their intersection.
Example:Given nums1 =[1, 2, 2, 1], nums2 = [2, 2], return [2, 2].
Note:

  • Each element in the result should appear as many times as it shows in both arrays.
  • The result can be in any order.

Follow up:

  • What if the given array is already sorted? How would you optimize your algorithm?
  • What if nums1's size is small compared to nums2's size? Which algorithm is better?
  • What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?
class Solution {
public:
    vector<int> intersect(vector<int>& nums1, vector<int>& nums2) {
        map<int, int> m = map<int, int>();
        vector<int> r = vector<int>();
        for(int i=0;i<nums1.size();i++)
            m[nums1[i]] += 1;
        for(int i=0;i<nums2.size();i++){
            if(m[nums2[i]] > 0){
                r.push_back(nums2[i]);
                m[nums2[i]]-=1;
            }
        }
        return r;
    }
};

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