CUC-SUMMER-9-A

A - Holidays

Codeforces Round #350 (Div. 2)

On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input
The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output
Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Example
Input
14
Output
4 4
Input
2
Output
0 2

Note
In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.

题意：在火星上一周与地球相同，周一到周五为工作日，周六周日为周末，已知火星一年有x天，求周末最多和最少有几天

解法：总天数除以7，余数分三种情况讨论，x<=2, 2<x<=5, 5<x

代码：

#include<iostream>
using namespace std;
int main()
{
    int n,r,x,y;
    cin>>n;
    r=n%7;
    x=n/7*2;
    y=x;
    if(r<=2)
        y+=r;
    else if(r<=5)
        y+=2;
    else{
        y+=2;
        x+=r-5;
    }
    cout<<x<<" "<<y<<endl;
    return 0;
}