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LeetCode-624. Maximum Distance i

LeetCode-624. Maximum Distance i

作者: 冷灬叶枫 | 来源:发表于2017-07-11 14:37 被阅读71次

Given m arrays, and each array is sorted in ascending order. Now you can pick up two integers from two different arrays (each array picks one) and calculate the distance. We define the distance between two integers a and b to be their absolute difference |a-b|. Your task is to find the maximum distance.

Example 1:

Input:
[[1,2,3],
[4,5],
[1,2,3]]
Output: 4
Explanation:
One way to reach the maximum distance 4 is to pick 1 in the first or third array and pick 5 in the second array.
Note:

Each given array will have at least 1 number. There will be at least two non-empty arrays.
The total number of the integers in all the m arrays will be in the range of [2, 10000].
The integers in the m arrays will be in the range of [-10000, 10000].

func maxDistance(_ arrays: [[Int]]) -> Int {
    var result = Int.min
    var minValue = arrays[0][0]
    var maxValue = arrays[0][arrays[0].count-1]
    
    for i in 1..<arrays.count {
        let arr = arrays[i]
        result = max(result, abs(minValue - arr[arr.count-1]))
        result = max(result, abs(maxValue - arr[0]))
        minValue = min(minValue, arr[0])
        maxValue = max(maxValue, arr[arr.count-1])
    }
    
    return result
}

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