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mysql-part1

mysql-part1

作者: cure_py | 来源:发表于2017-06-18 20:12 被阅读0次

    http://blog.sina.com.cn/s/blog_5b6cb950010116om.html

    1. 建表
      cat_id
    create table if not exists cate(cat_id int(11) not null auto_increment primary key,
    cat_name varchar(11) character set utf8 collate utf8_bin not null);
    

    goods

    create table if not exists goods(
    goods_id int(11) not null auto_increment primary key,
    goods_name varchar(11) character set utf8 collate utf8_bin not null,
    cat_id int(11) not null);
    

    order_goods

    CREATE TABLE IF NOT EXISTS order_goods(
      order_goods_id int(11) NOT NULL AUTO_INCREMENT primary key,
      order_id int(11) NOT NULL,
      goods_id int(11) NOT NULL,
      goods_num int(11) NOT NULL);
    

    order_info

    CREATE TABLE IF NOT EXISTS order_info(
      order_info_id int(11) NOT NULL AUTO_INCREMENT  PRIMARY KEY,
      test2 varchar(11) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL);
    
    1. 插入数据
    insert into cate (cat_id, cat_name) values
    (1, '分类1'),
    (2, '分类2');
    
    insert into goods values
    (2, '书', 1),
    (3, '手机', 2),
    (4, '水壶', 1),
    (5, '没人买', 2);
    
    insert into order_goods values
    (1, 2, 2, 3),
    (2, 2, 3, 2),
    (3, 3, 4, 1),
    (4, 3, 4, 1),
    (5, 4, 4, 4);
    
    INSERT INTO order_info VALUES
    (2, '测试1'),
    (3, '测试2'),
    (4, '测试3');
    
    1. 题意----根据订单商品表(order_goods)列出商品(goods)卖的数量
      逻辑是----先合并,再根据合并后的表进行groupby,进行sum
    select g.goods_name, ifnull(sum(og.goods_num),0) as sell_num
    from goods as g
    left join order_goods as og on g.goods_id = og.goods_id
    group by g.goods_id
    
    1. 根据订单商品表(order_goods)列出商品卖的数量,且列出该类别
    select g.goods_name, c.cat_name, ifnull(sum(og.goods_num),0) as sell_num
    from goods as g
    left join order_goods as og on g.goods_id = og.goods_id
    left join cate as c on c.cat_id = g.cat_id
    group by g.goods_id;
    
    1. 根据订单商品表(order_goods)、指定类别ID(cat_id =1),列出商品卖的数量,且列出该类别
      group by 必须在where语句后
    select g.goods_name, c.cat_name, ifnull(sum(og.goods_num),0) as sell_num
    from goods as g
    left join order_goods as og on g.goods_id = og.goods_id
    left join cate as c on c.cat_id = g.cat_id
    where c.cat_id = 1
    group by g.goods_id;
    

    6.最后的

    select g.*, c.cat_name,
    sum(
    case when(oi.order_status='7' or oi.order_status='5')
    and(oi.pay_status='2')
    and(oi.shipping_status='2' or oi.shipping_status='1')
    then og.goods_number
    else o end) as sell_num
    FROM  `tdm_goods` AS g
    LEFT JOIN  `tdm_category` AS c ON g.cat_id = c.cat_id
    LEFT JOIN  `tdm_order_goods` AS og ON g.goods_id = og.goods_id
    LEFT JOIN  `tdm_order_info` AS oi ON oi.order_id = og.order_id)
    where 1
    AND g.brand_id =  '65'
    AND g.is_delete =0
    AND g.is_on_sale =1
    GROUP BY g.goods_id
    order by sell_num desc;
    

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