URL地址切分（urlparse得到想要的）

例如想得到'/dp/B0013EIXX8‘

from urllib.parseimport urlparse

url ="https://www.amazon.com/dp/B0013EIXX8"

url_parsed = urlparse(url)

1.print(url_parsed)

2.print(url_parsed.path+'?'+url_parsed.query)

输出结果：

1的输出：ParseResult(scheme='https', netloc='www.amazon.com', path='/dp/B0013EIXX8', params='', query='', fragment='')

2的输出:/dp/B0013EIXX8?