获得query避免value里有=的bug

var getQueryParams = exports.getQueryParams =  function(){
    var arr = location.search.split(/(\?|&)/);
    var parmsObj = {};
    for (var i = 0; i < arr.length; i++) {
        if(arr[i].indexOf('=') != -1){
            var keyValue = arr[i].match(/([^\=]*)\=(.*)/);
            parmsObj[keyValue[1]] = decodeURIComponent(keyValue[2]);
        }
    };
    return parmsObj;
}