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leetcode123 & 309 & 714 买卖股票最佳时机

leetcode123 & 309 & 714 买卖股票最佳时机

作者: 奥利奥蘸墨水 | 来源:发表于2019-12-30 22:50 被阅读0次

    两次

    class Solution {
    public:
        int maxProfit(vector<int>& prices){
            return maxProfit_k_times(2,prices);
        }
    
        int maxProfit_k_times(int k_max, vector<int>& prices) {
    
            if (prices.empty()){
                return 0;
            }
    
            int len = prices.size();
    
            if (k_max > len / 2){
                return maxProfit_infinity(prices);
            }
    
            vector<vector<vector<int>>> dp(len, vector<vector<int>>(k_max + 1, vector<int>(2, 0)));
    
            for (int i = 0; i < len; i++){
                for (int k = 1; k <= k_max; k++){
                    if (i == 0){
                        dp[i][k][0] = 0;
                        dp[i][k][1] = -prices[i];
                    }else{
                        dp[i][k][0] = max(dp[i - 1][k][0], dp[i - 1][k][1] + prices[i]);
                        dp[i][k][1] = max(dp[i - 1][k][1], dp[i - 1][k - 1][0] - prices[i]);
                    }
                }
            }
    
            return dp[len - 1][k_max][0];
        }
    
        int maxProfit_infinity(vector<int>& prices){
            int cur_min = INT_MAX, cur_profit = 0, res = 0;
    
            for (auto x : prices){
                if (x - cur_min > cur_profit){
                    cur_profit = x - cur_min;
                }else{
                    res += cur_profit;
                    cur_profit = 0;
                    cur_min = x;
                }
            }
    
            return res + cur_profit;
        }
    };
    

    冷冻期

    class Solution {
    public:
        int maxProfit(vector<int>& prices) {
            if (prices.empty()){
                return 0;
            }
    
            int len = prices.size();
    
            vector<vector<int>> dp(len, vector<int>(2, 0));
    
            for (int i = 0; i < len; i++){
                if (i == 0){
                    dp[i][0] = 0;
                    dp[i][1] = -prices[i];
                }else{
                    dp[i][0] = max(dp[i - 1][0], dp[i - 1][1] + prices[i]);
                    
                    if (i >= 2)
                        dp[i][1] = max(dp[i - 1][1], dp[i - 2][0] - prices[i]);
                    else
                        dp[i][1] = max(dp[i - 1][1], dp[i - 1][0] - prices[i]);
                }
    
                // cout << dp[i][0] << " " << dp[i][1] << endl;
            }
    
            return dp[len - 1][0];
        }
    };
    

    手续费

    class Solution {
    public:
        int maxProfit(vector<int>& prices, int fee) {
            if (prices.empty()){
                return 0;
            }
    
            int len = prices.size();
    
            vector<vector<int>> dp(len, vector<int>(2, 0));
    
            for (int i = 0; i < len; i++){
                if (i == 0){
                    dp[i][0] = 0;
                    dp[i][1] = -prices[i];
                }else{
                    dp[i][0] = max(dp[i - 1][0], dp[i - 1][1] + prices[i] - fee);
                    dp[i][1] = max(dp[i - 1][1], dp[i - 1][0] - prices[i]);
                }
            }
    
            return dp[len - 1][0];
        }
    };
    

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