Description
Solution
1.直接分值递归搜索(代码可化简)
"""
Definition of TreeNode:
class TreeNode:
def __init__(self, val):
self.val = val
self.left, self.right = None, None
"""
class Solution:
"""
@param root: the root of binary tree
@return: the root of the minimum subtree
"""
def dfs(self,root):
if root.left is None and root.right is None:
if self.minimum > root.val:
self.minimum = root.val
self.sub = root
return root.val
sum =0
if root.left is not None:
left = self.dfs(root.left)
sum += left
if root.right is not None:
right = self.dfs(root.right)
sum += right
sum +=root.val
if self.minimum > sum:
self.minimum = sum
self.sub = root
return sum
def findSubtree(self, root):
self.minimum = 1e6
self.sub = root
self.dfs(root)
return self.sub
# write your code here
化简以后的代码(较为简单)
"""
Definition of TreeNode:
class TreeNode:
def __init__(self, val):
self.val = val
self.left, self.right = None, None
"""
class Solution:
"""
@param root: the root of binary tree
@return: the root of the minimum subtree
"""
def dfs(self,root):
if root is None:
return 0
sum =0
left = self.dfs(root.left)
sum += left
right = self.dfs(root.right)
sum += right
sum +=root.val
if self.minimum > sum:
self.minimum = sum
self.sub = root
return sum
def findSubtree(self, root):
self.minimum = 1e6
self.sub = root
self.dfs(root)
return self.sub
# write your code here
2.不使用额外的全局变量(在返回值做文章)
code from https://www.jiuzhang.com/solutions/minimum-subtree/#tag-highlight-lang-python
class Solution:
def findSubtree(self, root):
minimum, subtree, sum = self.helper(root)
return subtree
def helper(self, root):
if root is None:
return sys.maxsize, None, 0
left_minimum, left_subtree, left_sum = self.helper(root.left)
right_minimum, right_subtree, right_sum = self.helper(root.right)
sum = left_sum + right_sum + root.val
if left_minimum == min(left_minimum, right_minimum, sum):
return left_minimum, left_subtree, sum
if right_minimum == min(left_minimum, right_minimum, sum):
return right_minimum, right_subtree, sum
return sum, root, sum
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