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383. Ransom Note

383. Ransom Note

作者: a_void | 来源:发表于2016-09-13 20:02 被阅读0次

Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.

Each letter in the magazine string can only be used once in your ransom note.

class Solution {
public:
    bool canConstruct(string ransomNote, string magazine) {
        int buffer1[128] = {0};
        int buffer2[128] = {0};
        for(int i=0;i<ransomNote.size();i++) buffer1[ransomNote[i]] += 1;
        for(int i=0;i<magazine.size();i++) buffer2[magazine[i]] += 1;
        for(int i=0;i<128;i++){
            if(buffer1[i] > buffer2[i]) return false;
        }
        return true;
    }
};

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