===================== 解題思路 =====================
二分法檢查 如果 mid 的版本是 bad version 那說明至少 first bad version 會在 mid 或是 mid 之前 所以把範圍縮小到 right = mid, 反之則是 left = mid
===================== C++ code ====================
<pre><code>
/**
- class SVNRepo {
public:
static bool isBadVersion(int k);
- }
- you can use SVNRepo::isBadVersion(k) to judge whether
- the kth code version is bad or not.
*/
class Solution {
public:
/**
* @param n: An integers.
* @return: An integer which is the first bad version.
*/
int findFirstBadVersion(int n) {
// write your code here
int left = 0, right = n;
while(left + 1 < right)
{
int mid = left + (right - left) / 2;
if(SVNRepo::isBadVersion(mid)) right = mid;
else left = mid;
}
if(SVNRepo::isBadVersion(left)) return left;
else return right;
}
};
<code><pre>
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