Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array.
Formally the function should:
Return true if there exists i, j, k
such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return false.
Your algorithm should run in O(n) time complexity and O(1) space complexity.
Examples:
Given [1, 2, 3, 4, 5],
return true.
Given [5, 4, 3, 2, 1],
return false.<br
public boolean increasingTriplet(int[] nums) {
int min =Integer.MAX_VALUE;
int mid =Integer.MAX_VALUE;
for(int i=0;i<nums.length;i++) {
if(nums[i]<min) {
min=nums[i];
}else if(min<nums[i]&&nums[i]<mid) {
mid = nums[i];
}else {
if(nums[i]>mid) return true;
}
}
return false;
}
用两个标志 min mid。
网友评论