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文章作者:Tyan
博客:noahsnail.com | CSDN | 简书
1. Description
2. Solution
解析:Version 1,根据题意,需要先数组求和,然后再求跟目标的差值,为了添加最少数量的数字,因此每次都应添加极限数值,题目变成了算除法并对余数取整。
- Version 1
class Solution:
def minElements(self, nums: List[int], limit: int, goal: int) -> int:
total = sum(nums)
diff = goal - total
count = ceil(abs(diff) / limit)
return count
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