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 iOS应用跳转至app store 评分页

 iOS应用跳转至app store 评分页

作者: YuWenHaiBo | 来源:发表于2016-08-14 19:26 被阅读47次

    // 打开AppStore应用程序,进入评分区

     [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"https://itunes.apple.com/cn/app/fang-pin-hui-kan-fang-mai/id1031818254?mt=8"]];
    

    // 打开新的控制器,进入评分区
    // 苹果提供的框架

    StoreKit.framework

    
    SKStoreProductViewController *storeVC = [[SKStoreProductViewController alloc] init];
        storeVC.delegate = self;
        [storeVC loadProductWithParameters:@{SKStoreProductParameterITunesItemIdentifier :@"1031818254"}completionBlock:^(BOOL result, NSError * _Nullable error) {
            //block回调
            if(error){
                NSLog(@"error %@ with userInfo %@",error,[error userInfo]);
            }else{
                //模态弹出appstore
                [self presentViewController:storeVC animated:YES completion:^{
                    
                }
                 ];
            }
        }];
    
    
    
    // 评分完成调用
    - (void)productViewControllerDidFinish:(SKStoreProductViewController *)viewController
    {
        [self dismissViewControllerAnimated:YES completion:nil];
    }
    

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