直接上代码, 我们以下面的例子说明
for (i in 4 downTo 1 step 2) print(i) // 输出“42”
// downTo 定义
public infix fun Int.downTo(to: Int): IntProgression {
return IntProgression.fromClosedRange(this, to, -1)
}
// until 定义
public infix fun Int.until(to: Int): IntRange {
if (to <= Int.MIN_VALUE) return IntRange.EMPTY
return this .. (to - 1).toInt() // 此处可以看出 .. 与 until 的区别
}
// LongRange 定义
public class LongRange(start: Long, endInclusive: Long) : LongProgression(start, endInclusive, 1), ClosedRange<Long> {
override val start: Long get() = first
override val endInclusive: Long get() = last
override fun contains(value: Long): Boolean = first <= value && value <= last
override fun isEmpty(): Boolean = first > last
override fun equals(other: Any?): Boolean =
other is LongRange && (isEmpty() && other.isEmpty() ||
first == other.first && last == other.last)
override fun hashCode(): Int =
if (isEmpty()) -1 else (31 * (first xor (first ushr 32)) + (last xor (last ushr 32))).toInt()
override fun toString(): String = "$first..$last"
companion object {
/** An empty range of values of type Long. */
public val EMPTY: LongRange = LongRange(1, 0)
}
}
// LongProgression 定义
public open class LongProgression
internal constructor
(
start: Long,
endInclusive: Long,
step: Long
) : Iterable<Long> {... }
// ClosedRange 定义
public interface ClosedRange<T: Comparable<T>> {
/**
* The minimum value in the range.
*/
public val start: T
/**
* The maximum value in the range (inclusive).
*/
public val endInclusive: T
/**
* Checks whether the specified [value] belongs to the range.
*/
public operator fun contains(value: T): Boolean = value >= start && value <= endInclusive
/**
* Checks whether the range is empty.
*/
public fun isEmpty(): Boolean = start > endInclusive
}
public infix fun IntProgression.step(step: Int): IntProgression {
checkStepIsPositive(step > 0, step)
return IntProgression.fromClosedRange(first, last, if (this.step > 0) step else -step)
}
其中 infix 表示中缀表示法, operator 表示 重载操作符的函数
infix fun Int.shl(x: Int): Int { …… }
// 用中缀表示法调用该函数
1 shl 2
// 等同于这样
1.shl(2)
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