class Solution {
public String longestCommonPrefix(String[] strs) {
if(strs.length==0)
return "";
if(strs.length==1)
return strs[0];
return find(strs, strs[0],1);
}
private String find(String[] strs, String prefix, int pos){
if(pos==strs.length)
return prefix;
if(prefix.equals("")||strs[pos].equals("")){
return "";
}
int ed = Math.min(strs[pos].length(),prefix.length());
for(int i=0;i<ed;i++){
if(strs[pos].charAt(i)!=prefix.charAt(i)){
return find(strs, prefix.substring(0,i),pos+1);
}
}
return find(strs, prefix.substring(0,ed),pos+1);
}
}
使用java.lang.String.indexOf(String)方法(更快)
class Solution {
public String longestCommonPrefix(String[] strs) {
if(strs==null || strs.length==0) return "";
String prefix = strs[0];
int i=1;
while(i<strs.length){
while(strs[i].indexOf(prefix)!=0)
prefix = prefix.substring(0,prefix.length()-1);
i++;
}
return prefix;
}
}
贴出java.lang.String.indexOf(String)最终实现
/**
* Code shared by String and StringBuffer to do searches. The
* source is the character array being searched, and the target
* is the string being searched for.
*
* @param source the characters being searched.
* @param sourceOffset offset of the source string.
* @param sourceCount count of the source string.
* @param target the characters being searched for.
* @param targetOffset offset of the target string.
* @param targetCount count of the target string.
* @param fromIndex the index to begin searching from.
*/
static int indexOf(char[] source, int sourceOffset, int sourceCount,
char[] target, int targetOffset, int targetCount,
int fromIndex) {
if (fromIndex >= sourceCount) {
return (targetCount == 0 ? sourceCount : -1);
}
if (fromIndex < 0) {
fromIndex = 0;
}
if (targetCount == 0) {
return fromIndex;
}
char first = target[targetOffset];
int max = sourceOffset + (sourceCount - targetCount);
for (int i = sourceOffset + fromIndex; i <= max; i++) {
/* Look for first character. */
if (source[i] != first) {
while (++i <= max && source[i] != first);
}
/* Found first character, now look at the rest of v2 */
if (i <= max) {
int j = i + 1;
int end = j + targetCount - 1;
for (int k = targetOffset + 1; j < end && source[j]
== target[k]; j++, k++);
if (j == end) {
/* Found whole string. */
return i - sourceOffset;
}
}
}
return -1;
}
网友评论