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Semaphore(信号量)

Semaphore(信号量)

作者: 程序员大黑鱼 | 来源:发表于2020-07-19 23:35 被阅读0次

    Semaphore(信号量)

    作用

    Semaphore的作用是控制并发访问的线程数目。

    核心方法

    //参数permits表示许可数目,即同时可以允许多少线程进行访问  
    public Semaphore(int permits);
    //这个多了一个参数fair表示是否是公平的,即等待时间越久的越先获取许可 
    public Semaphore(int permits, boolean fair);
    //获取一个许可,如果没有继续等待
    public void acquire() throws InterruptedException;
    //尝试获取一个许可,获取到返回true,未获取到返回false
    public boolean tryAcquire();
    //尝试获取指定时间内的1个许可,超时后,不再尝试获取许可,直接返回false
    public boolean tryAcquire(long timeout, TimeUnit unit);
    //释放一个许可
    public void release();
    //获取多个许可
    public void acquire(int permits) throws InterruptedException;
    public void acquireUninterruptibly(int permits);
    //尝试获取多个许可,获取到后返回true,未获取到返回false
    public boolean tryAcquire(int permits);
    //尝试获取指定时间内的多个许可,超时后,不再尝试获取许可,直接返回false
    public boolean tryAcquire(int permits, long timeout, TimeUnit unit) throws InterruptedException;
    //释放多个许可
    public void release(int permits);
    

    示例

    获取一个许可

    import lombok.extern.slf4j.Slf4j;
    
    import java.util.concurrent.ExecutorService;
    import java.util.concurrent.Executors;
    import java.util.concurrent.Semaphore;
    
    /**
     * @author scottxuan
     */
    @Slf4j
    public class SemaphoreExample1 {
        private final static int threadCount = 12;
        public static void main(String[] args) {
            //控制并发数目为3 (许可的总数)
            Semaphore semaphore = new Semaphore(3);
            ExecutorService executor = Executors.newCachedThreadPool();
            for (int i = 0; i < threadCount; i++) {
                final int num = i;
                executor.execute(()->{
                    try {
                        //获取一个许可
                        semaphore.acquire();
                        update(num);
                        //释放一个许可
                        semaphore.release();
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                });
            }
            executor.shutdown();
        }
    
        private static void update(int num) throws InterruptedException {
            log.info("current num {}",num);
            //线程睡眠可以更明显的看到效果
            Thread.sleep(3000);
        }
    }
    
    //输出结果(注意时间,每次执行3个线程,间隔是设置的线程睡眠的时间3s)
    //23:00:34.761 [pool-1-thread-3] INFO scottxuan.semaphore.SemaphoreExample1 - current num 2
    //23:00:34.761 [pool-1-thread-2] INFO scottxuan.semaphore.SemaphoreExample1 - current num 1
    //23:00:34.761 [pool-1-thread-1] INFO scottxuan.semaphore.SemaphoreExample1 - current num 0
    
    //23:00:37.768 [pool-1-thread-6] INFO scottxuan.semaphore.SemaphoreExample1 - current num 5
    //23:00:37.768 [pool-1-thread-5] INFO scottxuan.semaphore.SemaphoreExample1 - current num 4
    //23:00:37.768 [pool-1-thread-4] INFO scottxuan.semaphore.SemaphoreExample1 - current num 3
    
    //23:00:40.778 [pool-1-thread-8] INFO scottxuan.semaphore.SemaphoreExample1 - current num 7
    //23:00:40.778 [pool-1-thread-9] INFO scottxuan.semaphore.SemaphoreExample1 - current num 8
    //23:00:40.778 [pool-1-thread-7] INFO scottxuan.semaphore.SemaphoreExample1 - current num 6
    
    //23:00:43.791 [pool-1-thread-10] INFO scottxuan.semaphore.SemaphoreExample1 - current num 9
    //23:00:43.791 [pool-1-thread-11] INFO scottxuan.semaphore.SemaphoreExample1 - current num 10
    //23:00:43.791 [pool-1-thread-12] INFO scottxuan.semaphore.SemaphoreExample1 - current num 11
    
    

    获取多个许可

    import lombok.extern.slf4j.Slf4j;
    
    import java.util.concurrent.ExecutorService;
    import java.util.concurrent.Executors;
    import java.util.concurrent.Semaphore;
    
    /**
     * @author scottxuan
     */
    @Slf4j
    public class SemaphoreExample2 {
        private final static int threadCount = 12;
        public static void main(String[] args) {
            //控制并发量为3
            Semaphore semaphore = new Semaphore(3);
            ExecutorService executor = Executors.newCachedThreadPool();
            for (int i = 0; i < threadCount; i++) {
                final int num = i;
                executor.execute(()->{
                    try {
                        //获取多个许可,这里一个线程直接获取3个,就没有了,第二个线程等他执行完释放后,才可以执行
                        semaphore.acquire(3);
                        update(num);
                        //释放多个许可
                        semaphore.release(3);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                });
            }
            executor.shutdown();
        }
    
        private static void update(int num) throws InterruptedException {
            log.info("current num {}",num);
            Thread.sleep(1000);
        }
    }
    
    //结果输出  注意时间  每秒,输出1次
    //23:15:44.148 [pool-1-thread-1] INFO scottxuan.semaphore.SemaphoreExample2 - current num 0
    //23:15:45.169 [pool-1-thread-2] INFO scottxuan.semaphore.SemaphoreExample2 - current num 1
    //23:15:46.179 [pool-1-thread-3] INFO scottxuan.semaphore.SemaphoreExample2 - current num 2
    //23:15:47.194 [pool-1-thread-4] INFO scottxuan.semaphore.SemaphoreExample2 - current num 3
    //23:15:48.196 [pool-1-thread-5] INFO scottxuan.semaphore.SemaphoreExample2 - current num 4
    //23:15:49.199 [pool-1-thread-6] INFO scottxuan.semaphore.SemaphoreExample2 - current num 5
    //23:15:50.214 [pool-1-thread-7] INFO scottxuan.semaphore.SemaphoreExample2 - current num 6
    //23:15:51.214 [pool-1-thread-8] INFO scottxuan.semaphore.SemaphoreExample2 - current num 7
    //23:15:52.226 [pool-1-thread-9] INFO scottxuan.semaphore.SemaphoreExample2 - current num 8
    //23:15:53.227 [pool-1-thread-10] INFO scottxuan.semaphore.SemaphoreExample2 - current num 9
    //23:15:54.239 [pool-1-thread-11] INFO scottxuan.semaphore.SemaphoreExample2 - current num 10
    //23:15:55.242 [pool-1-thread-12] INFO scottxuan.semaphore.SemaphoreExample2 - current num 11
    

    尝试获取许可

    import lombok.extern.slf4j.Slf4j;
    
    import java.util.concurrent.ExecutorService;
    import java.util.concurrent.Executors;
    import java.util.concurrent.Semaphore;
    
    /**
     * @author scottxuan
     */
    @Slf4j
    public class SemaphoreExample3 {
        private final static int threadCount = 12;
        public static void main(String[] args) {
            //控制并发量为3
            Semaphore semaphore = new Semaphore(3);
            ExecutorService executor = Executors.newCachedThreadPool();
            for (int i = 0; i < threadCount; i++) {
                final int num = i;
                executor.execute(()->{
                    try {
                        //尝试获取1个许可
                        if (semaphore.tryAcquire()) {
                            update(num);
                            //释放一个许可
                            semaphore.release();
                        }
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                });
            }
            executor.shutdown();
        }
    
        private static void update(int num) throws InterruptedException {
            log.info("current num {}",num);
            Thread.sleep(1000);
        }
    }
    
    //输出结果 只有3个线程执行完了  3个线程获取到许可后,并发数目(许可总数)用完了 后续的线程获取不到,无法进入if中的代码
    //23:17:35.375 [pool-1-thread-1] INFO scottxuan.semaphore.SemaphoreExample3 - current num 0
    //23:17:35.375 [pool-1-thread-2] INFO scottxuan.semaphore.SemaphoreExample3 - current num 1
    //23:17:35.375 [pool-1-thread-3] INFO scottxuan.semaphore.SemaphoreExample3 - current num 2
    
    尝试获取带时间参数的许可
    import lombok.extern.slf4j.Slf4j;
    
    import java.util.concurrent.ExecutorService;
    import java.util.concurrent.Executors;
    import java.util.concurrent.Semaphore;
    import java.util.concurrent.TimeUnit;
    
    /**
     * @author scottxuan
     */
    @Slf4j
    public class SemaphoreExample4 {
        private final static int threadCount = 12;
        public static void main(String[] args) {
            //控制并发量为3(许可总数)
            Semaphore semaphore = new Semaphore(3);
            ExecutorService executor = Executors.newCachedThreadPool();
            for (int i = 0; i < threadCount; i++) {
                final int num = i;
                executor.execute(()->{
                    try {
                        //尝试获取3s内的许可,获取不到则返回false
                        if (semaphore.tryAcquire(3, TimeUnit.SECONDS)) {
                            update(num);
                            //释放一个许可
                            semaphore.release();
                        }
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                });
            }
            executor.shutdown();
        }
    
        private static void update(int num) throws InterruptedException {
            log.info("current num {}",num);
            Thread.sleep(1000);
        }
    }
    
    //输出结果
    //总计12个线程,并发为3,线程执行沉睡1s,所以每次执行3个线程,在第3次执行完成后,线程的睡眠总时间也到达3s了,
    //尝试获取指定时间内的许可失败后,直接返回false
    //23:25:11.166 [pool-1-thread-2] INFO scottxuan.semaphore.SemaphoreExample4 - current num 1
    //23:25:11.166 [pool-1-thread-3] INFO scottxuan.semaphore.SemaphoreExample4 - current num 2
    //23:25:11.166 [pool-1-thread-1] INFO scottxuan.semaphore.SemaphoreExample4 - current num 0
    
    //23:25:12.176 [pool-1-thread-5] INFO scottxuan.semaphore.SemaphoreExample4 - current num 4
    //23:25:12.176 [pool-1-thread-6] INFO scottxuan.semaphore.SemaphoreExample4 - current num 5
    //23:25:12.176 [pool-1-thread-4] INFO scottxuan.semaphore.SemaphoreExample4 - current num 3
    
    //23:25:13.187 [pool-1-thread-7] INFO scottxuan.semaphore.SemaphoreExample4 - current num 6
    //23:25:13.187 [pool-1-thread-8] INFO scottxuan.semaphore.SemaphoreExample4 - current num 7
    //23:25:13.187 [pool-1-thread-9] INFO scottxuan.semaphore.SemaphoreExample4 - current num 8
    

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