PAT 甲级1082 Read Number in Chines

说真的这道题按照算法笔记上写应该会比较简单，能完美避免末尾0的问题。但是我就是头铁，就是要从头到尾的进行处理，事实证明难是不难，就是要考虑的内容太多

#include <iostream>
#include <cstdio>
#include <cstring>
#include<iostream>
#include <string.h>
using namespace std; 
int main(){
    int start=0;
    bool istotoal=true;
    char w[][11] = {"Yi","Qian","Bai","Shi","Wan","Qian","Bai","Shi",""};
    char n[][11] = {"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
    char str[15];
    cin.getline(str,15);

    int length=strlen(str);
     if(length==1 && str[0]=='0'){
        printf("ling");
        return 0;
    }
    if(str[0]=='-'){
        printf("Fu");
        start=1;
    }
    int shulen=length-start;
    for(int i=start;i<length;i++){
        if(str[i]=='0'){
             if(i==length-5 && istotoal==false)printf(" Wan"); 

           while(str[i+1]=='0'&& (i+1)!=length-1 && (i+1)!=length-5){
               i++;
           }
        if(((i+1)==length-5 && str[i+1]=='0')||((i+1)==length-1 && str[i+1]=='0')||i==length-1||i==length-5){
            
        }else{
            printf(" ling");
        }
              //if((i+1)==length-5 && istotoal==false){
             //printf(" Wan"); 
              //}
        }else{
            if(i==length-1){
                int curnum=str[i]-'0';
                if(i>0)printf(" ");
                printf("%s",n[curnum]);
            }else{
            int curnum=str[i]-'0';
            if(i<length-5 && length-i!=9)istotoal=false;
            if(i>0)printf(" ");
            printf("%s %s",n[curnum],w[8-length+1+i]);
            }
        }
        
    }
    return 0;
}

当然AC是肯定的