获取url中的参数

  getStrParam(str, name) {
    var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i");
    var r = str.match(reg);
    if (r != null) return r[2];
    return '';
  },

使用

          let splitIndex = res.result.indexOf('?');
          let str = res.result.substring(splitIndex + 1);
          let result = that.getStrParam(str, 'did');